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script language="JavaScript">
');
}
window.captureEvents(Event.MOUSEMOVE);

function nsMouse(evnt){
Xpos = window.pageYOffset+evnt.pageX;
Ypos = window.pageYOffset+evnt.pageY;
}
}
else{
document.write('');
for (i=0; i ');
}
document.write('');

function ieMouse(){
Ypos=document.body.scrollTop+event.y;
Xpos=document.body.scrollLeft+event.x;
}
}

function MouseFollow(){
if (brwsr){window.onMouseMove = nsMouse}
else {window.document.onmousemove = ieMouse}
ay = Math.round(Ay += ((Ypos) - Ay) * 4/40);
ax = Math.round(Ax += ((Xpos) - Ax) * 4/40);
setTimeout('MouseFollow()',10);
}

function colourStep(){
count+=move;
if (count >= dots) {count=0;count_a+=move}
if (count_a == CoLoUrS.length) count_a=0;
if (brwsr) document.layers["a"+count].bgColor=CoLoUrS[count_a];
else ieDivs[count].style.background=CoLoUrS[count_a];
setTimeout('colourStep()',10)
}

function TwistnSpin(){
if (brwsr){
for (i = 0; i < dots; i++)
{
var templayer="a"+i
document.layers[templayer].top=ay+cntr*Math.cos((currStep+i*4)/10.2)*Math.cos(currStep/30)
document.layers[templayer].left=ax+cntr*Math.sin((currStep+i*4)/10.2);
}
}
else{
for (i=0;i < dots;i++)
{
ieDivs[i].style.top=ay+cntr*Math.cos((currStep+i*4)/10.2)*Math.cos(currStep/10);
ieDivs[i]
50% Discount
Relation: Is a Secret
Phone Model: n73 5300
Skinner Since: 16 years ago
Last Login: 15 years ago

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